Question

What are the components of vector B if its magnitude is 18 m and makes an angle of 112° with the +x-axis?

Bx

 = −6.74 m,  By  = 16.7 m

Bx  = 6.74 m,  By  = −16.7 m

Bx  = 16.7 m,  By  = −6.74 m

Answer 1

Calling B=18 m the magnitude of the vector, its components on the x- and y- axis are given by:

`B_x = B \cos \theta =(18 m)(\cos 112^(\circ))=-6.74 m`

`B_y = B \sin \theta = (18 m)(\sin 112^(\circ)) = 16.7 m`
Therefore, the correct answer is the first one:
Bx = −6.74 m, By = 16.7 m