Question

Algebra help

What is an equation for the translation of (x-2)^2+(y+1)^2=16 by 5 units left and 4 units up?

Answer 1

The answer to this question is (x+3)^2 + (y-3)^2 = 16 because
(x-2+5)^2+(y+1-4)^2=16 ⇔ (x+3)^2 + (y-3)^2 = 16

Answer 2

`(x +3)^(2) +(y -3)^2 = 16`

Explanation:

The given equation is an equation of circle.

`(x -2)^(2) + (y +1)^2 = 16`

The equation translated 5 units left and 4 units up.

Which means we have to add 5 with x and subtract 4 with y.

That is replace x by x + 5 and replace y by y - 4, we get

`(x+5 -2)^(2) + (y -4 +1)^2 = 16`

Now we have to simplify it.

`(x +3)^(2) +(y -3)^2 = 16`