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How do you simplify #(-3 - 2i)(-3 + 3i)#?

How do you simplify #(-3 - 2i)(-3 + 3i)#?
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How do you simplify #(-3 - 2i)(-3 + 3i)#?

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User Alan Ho
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1 Answer

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So, ( -3 - 2i )( -3 + 3i ) = 9 - 9i +6i - 6i^2 = 9 - 3i - 6·(-1) = 9 + 6 - 3i = 15 - 3i;
We have / 15 +(- 3)i / = 15.29;
\sqrt{ 15^(2) + (-3)^(2) } = √(225 + 9) = √(234) =
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User Parimal
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