Question

What is the missing constant term in the perfect square that starts with x^2+6xx 2 +6xx, start superscript, 2, end superscript, plus, 6, x ?

Answer 1

For this case we have the following polynomial:
x ^ 2 + 6x
The missing value to complete the square is given by:
x ^ 2 + 6x + (6/2) ^ 2
Rewriting we have:
x ^ 2 + 6x + (3) ^ 2
x ^ 2 + 6x + 9
Then, completing the square we have:
(x + 3) ^ 2
Answer:
the missing constant term in the perfect square is:
9