Question

Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.

Answer 1

Hello!!

Equation forms:


`y = (x^2)/(4) + (x)/(2) + (13)/(4)`

Therefore,
`x^2 - 2x + 4y - 13 = 0`

And, this is how your graph would look

Good luck :)