Question

HELP QUICK I ONLY HAVE 1 CHANCE

Milan uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled:
1 10
2 8
3 33
4 29
5 11
6 9
Heads Tails
29 71

Using Milan's simulation, what is the probability of rolling a 5 on the number cube and the coin landing on tails?

fraction 11 over 10,000
fraction 71 over 10,000
fraction 82 over 10,000
fraction 781 over 10,000

Answer 1

`(781)/(10000)`

Explanation:

Given :

Number on the Cube Number of Times Rolled:

1 10

2 8

3 33

4 29

5 11

6 9

Heads Tails

29 71

Total number of times cube rolled = 100

Total number of coin rolled = 100

Number of times getting 5 on a cube = 11

Number of times getting tails = 71

Now probability of getting 5 on the number cube :

=
`\frac{\text{Number of times 5 occurred on a cube}}{\text{Number of times cube is rolled}}`

=
`(11)/(100)`

Probability of getting tails =
`\frac{\text{Number of times tails occurred on a coin}}{\text{Number of times coin is rolled}}`

=
`(71)/(100)`

Probability of rolling a 5 on the number cube and the coin landing on tails =
`(11)/(100) * (71)/(100)`

=
`(781)/(10000)`

Thus the probability of rolling a 5 on the number cube and the coin landing on tails is
`(781)/(10000)`

Answer 2

Short Answer D
Remark
Thank you for trying to pose the question so clearly.

Givens
T = 71 times
5 being rolled = 11

Substitution and solution.
P(T) = 71/100
P(6) = 11/100
P(Both) = P(T) * P(6)
P(Both) = 71/100 * 11/100

P(both) = (71 * 11) / 10000
P(Both) = 781/10000