Question

Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

Answer 1

We have to compute first its force before we can get the work done on the box.

Force = m * a
m = 60 newtons
a = cos30 (since Roger applies force parallel to the incline, we will use cosine)
F = 60 * cos30
F = 51.9615... N

Work done = F * d
F = 51.9615... N
d = 10 meters
W = 51.9615... N * 10 meters
W = 519.6152... Joules or 520 J