Question

Find the 16th term of the arithmetic sequence whose common difference is d=6 and whose first term is a 1=3

Answer 1

93

Explanation:

This question is on Arithmetic sequence, and we can find the 16th term using the Arithmetic sequence formula below;

aₙ= a₁ + (n-1)d

Where n= nth term in that particular sequence.

n₁= first term in the particular sequence.

d= common sequence between the terms.

Given:

d=6

a₁ =3.

Using the formula above,

a₁₆= 3 + (16-1)6

= 3+(15)6

=3+90

=93

Hence, the the 16th term of the arithmetic sequence is 93