Question

Jeremy, Sue, and Holly are siblings. Sue was born three years before Holly, and Jeremy was born five years before Sue. The product of Sue's age and Jeremy's age is at most 150. If x represents the age of Holly, which inequality can be used to find the age of each sibling?

Answer 1

Answer: x^2+11x+24 </= 150

Answer 2

Inequality to find the age of siblings is x²+ 11x + 24 ≤ 150.

Explanation:

Let the age of Holly is x years. Now from the statements of the question we will form the equations.

Sue was born three years before Holly.

Sue = Holly + 3 = x + 3------(1)

Jeremy = Sue + 5

From equation (1)

Jeremy = (x + 3) + 5 = x + 8------(2)

Now statement says the product of Sue's age and Jeremy's age is at most 150.

Sue × Jeremy ≤ 150

(x + 3)(x + 8) ≤ 150

x² + 11x + 24 ≤ 150

Therefore inequality x² + 11x + 24 ≤ 150 can be used to find the age of each sibling.