Question

Mr. Nguyen (65 kg) whirls a yellow ball (0.045 kg) around on a string by exerting a force of 15 N on it. The radius of the circle he makes is 0.58 m.

What is the frequency of revolution that the ball has in hertz? (2 sig figs)

Answer 1

w = 23.97 revolutions/ s

Step-by-step explanation:

F = 15 N

r = 0.58 m

mass of ball = 0.045 kg

According to Newton's law equal and opposite forces acts on a body.

so Fc= 15 N

Now

Fc = m* w² * r

⇒ w²= Fc / m*r

⇒w² = 15/ (0.045 * 0.58)

⇒w² = 574.7 Hz

⇒w =
`√(574.7)` revolutions/ s

⇒ w = 23.97 revolutions/ s