Question

. Gravitational force of attraction "F" exists between two-point masses A and B when a fixed distance separates them. After mass A is doubled and mass B is quartered, the gravitational attraction between the two masses is___________.

Answer 1

0.5F OR HALF OF PREVIOUS VALUE

Step-by-step explanation:

F= G Ma Mb/r²

now new force F1 is given as

F1= G ×2Ma × 0.25 Mb /r²

F1 = 2×0.25 ×Ma×Mb/r²

F1 = 0.5×Ma Mb/r²

F1= 0.5 F

Answer 2

Answer:8F

Step-by-step explanation:

Given

Gravitation attraction is F between A and B

if
`m_a` and
`m_b` is the mass of A and B respectively then

F is given by

`F=(Gm_am_b)/(r^2)`

where r=distance between them

if
`m_a` is doubled and
`m_b` is quadrupled then Force can be given by

`F'=(G* 2m_a* 4m_b)/(r^2)`

`F'=(8Gm_am_b)/(r^2)`

`F'=8F`

thus force becomes 8 times of initial value