Question

Two waiters are trying to get through a single door of a kitchen. One pushes on one side of a door 0.567 m from the hinge with a force of 257 N perpendicular to the door, the other pushes from the other side of the door 0.529 m from the hinge. The door doesn't move. With what perpendicular force is the second waiter pushing on the door?

Answer 1

`275.5 N`

Step-by-step explanation:

`F_(1)` = Force on one side of the door by first waiter = 257 N

`F_(2)` = Force on other side of the door by second waiter

`r_(1)` = distance of first force by first waiter from hinge = 0.567 m

`r_(2)` = distance of second force by second waiter from hinge = 0.529 m

Since the door does not move. hence the door is in equilibrium

Using equilibrium of torque by force applied by each waiter

`r_(1) F_(1) = r_(2) F_(2) \\(0.567) (257) = (0.529) F_(2)\\F_(2) = 275.5 N`