Answer:
Step-by-step explanation:
 The turntable that is rotating apparatus whose moment of inertia ( I ) is to be calculated is used as a spool of radius r. m mass is going down with acceleration a and rotating the apparatus with the help of cord with tension T wound around it
For motion of weight m 
mg - T = ma 
and for the motion of spool or apparatus 
Tr = I a/r 
T = Ia/r²
mg - Ia/r² = ma 
mg = Ia/r² + ma 
a ( I/r² + m ) = mg
When the counterweight m is released from rest it descends through a distance h, acquiring a speed v
v² = 2ah 
a = v² / 2h
v² / 2h ( I/r² + m ) = mg
( I/r² + m ) = 2mgh / v²
 I/r² = 2mgh / v²- m 
I = r² (2mgh / v²- m )
= mr² ( 2gh/ v² -1 )
Proved .