Question

238 93 Np → 0 -1 e+ ?​

Answer 1

Since the questions were asked so late, the only reason why I am answering this question is for the people who have the same question.

So, this question is asked like this:

Complete the following radioactive decay problem.

238 Np ⟶ 0 e + ___ ___

93 -1 ___

The answer is:

238 Pu

94

238 Np ⟶ 0 e + 238 Pu

93 -1 94

Answer 2

²³⁸₉₃Np → Pu₉₄²³⁸ + ⁰₋₁e

Step-by-step explanation:

²³⁸₉₃Np → Pu₉₄²³⁸ + ⁰₋₁e

Beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

⁴₆C → ¹⁴₇N + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.