Question

Jamal is skating on a sidewalk. His initial velocity is 0.0 m/s; 35 seconds later his velocity is 5.0 m/s. What is his acceleration? -0.14 m/s/s -7 m/s 0.14 m/s/s 7 m/s

Answer 1

answer is 0.1428

Step-by-step explanation:

Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²

Answer 2

`0.14m/s/s` or
`0.14m/s^2`

Step-by-step explanation:

Acceleration is the rate at which the velocity of a body increases per unit time. Its S.I unit is meters per second per second. Mathematically it is given as follows;

`a=(v_1-v_o)/(t)............(1)`

where
`v_1` is the velocity,
`v_o` the initial velocity and t is the time taken.

Given;

`v_o=0.0m/s\\v_1=5.0m/s\\t=35s\\a=?`

We substitute all into equation (1) to calculate a as follows;

`a=(5.0-0.0)/(35)\\a=(5)/(35)\\a=(1)/(7)\\a=0.14m/s/s`