Question

Given:
m∠LON=77 °
m∠LOM=9x+44 °
m∠MON=6x+3 °

Find ∠MON

Answer 1

15

Explanation:

Answer 2

`m\angle MON=15^o`

Explanation:

see the attached figure to better understand the problem

we know that

`m\angle LON=m\angle LOM+m\angle MON` ---> by addition angle postulate

substitute the given values

`77^o=(9x+44)^o+(6x+3)^o`

solve for x

`77=(15x+47)`

`15x=77-47`

`15x=30\\x=2`

Find the measure of angle MON

`m\angle MON=(6x+3)^o`

substitute the value of x

`m\angle MON=(6(2)+3)=15^o`