Question

The block in this illustration is floating in water, which has a density of 1.00 g/cm3 .

What is a good estimate of the density of the block if about 30 percent of the block is below water?


0.30 g/cm3

0.60 g/cm3

0.90 g/cm3

1.00 g/cm3

Answer 1

0.30 g/cm3

Step-by-step explanation:

0.3 g is 30% of 1.00g and since 30% of the block is underwater all you have to do is divide 1.00g by 30%.

Answer 2

0.3g/cm3

Step-by-step explanation:

Archimedes Principle states that any body partially or wholly submerged in a fluid at rest will experience an upward force which is equal in magnitude to the weight of the fluid displaced. This statement means volume of displaced fluid is equal to the magnitude of its buoyant force. Buoyant force is the weight of the floating object.

in other words, the weight of an object is equivalent to the mass of the liquid it displaces, so for a fully submerged object the weight is equal to the weight of the whole fluid. This finds application in the design of ships.

30/100= Density of block/Density of water

30/100 = 0.3g/cm3

Density of the block = 0.3 g/cm3