Question

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

25 L

11 L

15 L

Answer 1

15 L

Explanation:

Odyssey ware

Answer 2

15 L

Explanation:

If x is the liters of pure water, then:

0x + 0.25(10) = 0.10(x + 10)

2.5 = 0.10x + 1

1.5 = 0.10x

15 = x