What are the two zeros of the quadratic function defined by the expression 9x{2}-4

Question

asked Aug 28, 2022 126k views

1 Answer

Terryann · Answer 1 · 2022-09-03T14:42:28+0000

Answer:

The two zeros of the quadratic function are:

$x=(2)/(3),\:x=-(2)/(3)$

Explanation:

Given the expression

9x^2-4

In order to determine the zeros of the quadratic function, we get the equation

9x^2-4=0

Add 4 to both sides

9x^2-4+4=0+4

Simplify

9x^2=4

Divide both sides by 9

(9x^2)/(9)=(4)/(9)

Simplify

x^2=(4)/(9)

For x² = f(a) the solutions are:
$x=√(f\left(a\right)),\:\:-√(f\left(a\right))$

$x=\sqrt{(4)/(9)},\:x=-\sqrt{(4)/(9)}$

solving

$x=\sqrt{(4)/(9)}$

=(√(4))/(√(9))

=(2)/(3)

also solving

$x=-\sqrt{(4)/(9)}$

=-(√(4))/(√(9))

=-(2)/(3)

Therefore, the two zeros of the quadratic function are:

$x=(2)/(3),\:x=-(2)/(3)$