How many atoms of Al(OH)3 in a 72 gram sample? please show work

Question

asked Feb 2, 2020 169k views

1 Answer

Morteza Ziyaeimehr · Answer 1 · 2020-02-09T14:51:17+0000

Answer:

5.559*10^(23) atoms

Step-by-step explanation:

Molar Mass of Al(OH)3 = 78 g/mol

(72g/78g/mol)*(6.022*10^(23)atoms/mol) = 5.559*10^(23) atoms in 72 grams of Al(OH)3