Question

10.0 mL of a 0.770 M sodium hydroxide solution is transferred to a 50.0 mL volumetric flask followed by the addition of water to the calibration mark. What is the new concentration of the sodium hydroxide solution?

Answer 1

The new concentration of the sodium hydroxide solution = 0.154 M

Step-by-step explanation:

Considering :-

`Molarity_(1)* Volume_(1)=Molarity_(2)* Volume_(2)`

Given that:

`Molarity_(1)=0.770\ M`

`Volume_(1)=10.0\ mL`

`Volume_(2)=50.0\ mL`

`Molarity_(2)=?`

So,

`Molarity_(1)* Volume_(1)=Molarity_(2)* Volume_(2)`

`0.770\ M* 10.0\ mL=Molarity_(2)* 50.0\ mL`

`Molarity_2=(0.770* 10.0)/(50.0)\ M=0.154\ M`

The new concentration of the sodium hydroxide solution = 0.154 M