Question

Given f(x) = x3 – 2x2 – x + 2,
the roots of f(x) are?

Answer 1

{2,1,-1}

Explanation:

f(x) = x^3 – 2x^2 – x + 2

f(x) = (x - 2) (x - 1) (x + 1)

x=2

x=1

x=-1

Answer 2

`\displaystyle -1, 2, 1 = x`

Step-by-step explanation:

`\displaystyle [x^3 - 2x^2] - [x + 2] \\ x^2[x - 2] \: \: -1[x - 2] \\ \\ [x - 2][x^2 - 1] \\ \\ [x - 2][x - 1][x + 1]`

Then, when set to equal zero, you get the above roots.

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