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Vertex (-2,-2) point (-3,0) in standard form of the parabola

asked
User Etsa
by
8.3k points

1 Answer

5 votes

Answer:

y=2(x+2)^2-2

Explanation:

(h,k) --> (-2,-2)

y=ax^2+bx+c

y=a(x-h)^2+k<--- standard form

y=a(x+2)^2-2

0=a(-3+2)^2-2

a=2

y=2x^2+8x+6

answered
User DocRattie
by
8.2k points

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