Question

Find the real zeros 4x²-16x + 2.5x​

Answer 1

I am going to assume 2.5x is really 25x (typo).

First formulate the equality

`</p><p>4x^2-16x+25x=0 \\</p><p>4x^2+9x=0 \\</p><p>x(4x+9)=0 \\</p><p>`

Now two results emerge.

`x_1=0, x_2=-(9)/(4)`.

Hope this helps.