Question

Isopropyl alcohol is mixed with water to produce a 40.0 % (v/v) alcohol solution. How many milliliters of each component are present in 675 mL of this solution? Assume that volumes are additive.

Answer 1

Answer : The volume of water and alcohol present in 675 mL of this solution are 405 mL and 270 mL respectively.

Explanation :

As we are given that 40.0 % (v/v) alcohol solution. That means, 40.0 mL of alcohol present 100 mL of solution.

Now we have to calculable the volume of alcohol in 675 mL solution.

As, 100 mL of solution contains 40.0 mL of alcohol

So, 675 mL of solution contains
`(675)/(100)* 40.0=270mL` of alcohol

Thus, the volume of alcohol = 270 mL

Now we have to calculate the volume of water.

Volume of water = Volume of solution - Volume of alcohol

Volume of water = 675 mL - 270 mL

Volume of water = 405 mL

Thus, the volume of water = 405 mL

Hence, the volume of water and alcohol present in 675 mL of this solution are 405 mL and 270 mL respectively.