Question

The solubility of nitrogen gas at 25 ◦C and 1 atm is 6.8×10−4 mol/L. If the partial pressure of nitrogen gas in air is 0.76 atm, what is the concentration (molarity) of dissolved nitrogen?

Answer 1

Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L

Step-by-step explanation:

More the pressure of the gas, more will be its solubility.

So, for two different pressure, the relation between them is shown below as:-

`\frac {P_1}{C_1}=\frac {P_2}{C_2}`

Given ,

P₁ = 1 atm

P₂ = 0.76 atm

C₁ = 6.8 × 10⁻⁴ mol/L

C₂ = ?

Using above equation as:

`(1\ atm)/(6.8* 10^(-4)\ mol/L)=(0.76\ atm)/(C_2)`

`C_2=(0.76* 6.8* 10^(-4))/(1)\ mol/L`

Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L