Question

Determine the temperature of 2.6 moles of gas contained in a 5.00-L vessel at a pressure of 1.2atm.

Answer 1

28.108 K.

Explanation:

Given: Pressure (P)= 1.2atm

Number of moles (n)= 2.6 moles

Volume (V)= 5.00-L

Now finding the temperature (T).

Formula; T=
`(P* V)/(n* R)`

R is a constant factor which makes other factors work together.

There is a numerical value for R which we use is
`0.0821 * (L.atm)/(mole.K)`

∴ Temperature (T)=
`(1.2* 5)/(2.6* 0.0821 (L.atm)/(mol.K) )`

⇒ Temperature (T)=
`(6)/(0.21346) = 28.1083\ K`

∴ Temperature is 28.108 K