Question

Sarah attempts to do the popular physics trick of swinging a pail of water around in a vertical circle fast enough so the water doesn't spill out when the pail is upside down. If her arm is 0.417 meters long, what is the minimum speed with which she can swing the pail so the water does not spill out at the top of the path? (Assume that you may neglect the length of the pail).

Answer 1

The minimum speed will be 1.997 m /sec at which water does not spill out

Step-by-step explanation:

We have given that length of arm r = 0.417 m

Acceleration due to gravity
`g=9.8m/sec^2`

We have to find the minimum speed so that water does not spill out

We know that minimum speed is given by

`v_(min)=√(rg)=√(0.417* 9.8)=1.997m/sec`

So the minimum speed will be 1.997 m /sec at which water does not spill out