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The center of a circle lies on the line y = 3x + 1 and is tangent to the x-axis at (−2,0) .

What is the equation of the circle in standard form?

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Answer:

Explanation:

The center of a circle lies on the line y = 3x + 1 and is tangent to the x-axis at-example-1
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User Ribeye
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The equation of the circle in standard form is: (x + 2)² + (y - 1)² = 1

What is the equation of the circle?

The general form of the equation of a circle is:

(x - h)² + (y - k)² = r²

Where;

(h, K) is the coordinate of the center of the circle.

r is radius.

To find the equation of the circle in standard form, we need to determine the center and radius of the circle.

Since the center of the circle lies on the line y = 3x + 1 and is tangent to the x-axis at (-2,0), we can determine that the center of the circle is (-2,1) and the radius is 1.

Therefore, the equation of the circle in standard form is:

(x + 2)² + (y - 1)² = 1

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User Meilechh
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8.5k points

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