Question

When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of static friction between the car and the road is 0.88. Assuming your car doesnt skid, what is the force exerted on it by static friction?

Answer 1

Ff = 6058.5N

Step-by-step explanation:

The sum of forces is:

`Ff = m*a_c`

`Ff = m*V^2/R`

`Ff = 1900*13^2/53`

`Ff = 6058.5N`