Question

Point slope of (-4, 13) and (-2, 6)

Answer 1

y-13=-7/2(x+4)

Explanation:

y-y1=m(x-x1)

where m=slope and (x1, y1) is a point on the line

m=(y2-y1)/(x2-x1)

m=(6-13)/(-2-(-4))

m=-7/(-2+4)

m=-7/2

y-13=-7/2(x-(-4))

y-13=-7/2(x+4)