How much water should be added to 6 gallons of pure acid in order to obtain the 24% acid solution? HELP

Question

asked Sep 19, 2020 160k views

2 Answers

Nikita Took · Answer 1 · 2020-09-20T11:14:42+0000

Answer:

19 gallons

Explanation:

19 gallons

Huu Bao Nguyen · Answer 2 · 2020-09-23T14:03:22+0000

Answer:

19 gallons

Explanation:

Let x gallons be the amount of water which should be added to 6 gallons of pure acid in order to obtain the 24% acid solution.

Amount of water = x gallons

Amount of pure acid = 6 gallons

Amount of acid solution = x + 6 gallons

Amount of acid in acid solution = 24%

So, there are
0.24(x+6) gallons of acid in acid solution.

Hence,

0.24(x+6)=6

Solve this equation. Multiply it by 100:

$24(x+6)=600\\ \\24x+144=600\\ \\24x=600-144\\ \\24x=456\\ \\x=19\ gallons$