Question

A child’s toy sits on the bottom of a swimming pool in which the water depth is d=1.8 m. To a child standing at the pool edge, the toy appears to be a horizontal distance of 4.2 m away from the sidewall. Assume the child’s eyes are 3.5m above the bottom of the pool. What is the actual horizontal distance from the sidewall to the toy?

Answer 1

Horizontal distance is 1.28 + 2.04 = 3.32 m

Step-by-step explanation:

Given data:

from below figure

Applying Pythagoras theorem

from Snell's law

`(sin i)/(sin r) = (n_2)/(n_1) = ((EF)/(AB))/((DE)/(BD))`

`1.33 =( (2.04)/(√((3.5 -1.8)^2 + 2.04^2)))/((x)/(√(1.8^2 + x^2)))`

solving for x we have

`x^2 = 1.626`

x = 1.28

Horizontal distance is 1.28 + 2.04 = 3.32 m