Question

Plane microwaves are incident on a thin metal sheet that has a long, narrow slit of width 4.8 cm in it. The microwave radiation strikes the sheet at normal incidence. The first diffraction minimum is observed at θ = 42°. What is the wavelength of the microwaves?

Answer 1

`\lambda = 3.21 \ cm`

Step-by-step explanation:

given,

width of narrow slit = 4.8 cm

minimum angle of diffraction = θ = 42°

wavelength of the microwave = ?

condition for the diffraction for single slit diffraction

`d sin \theta = m \lambda`

for the first minima m = 1

`d sin \theta = \lambda`

wavelength of microwave radiation is equal to

`\lambda = d sin \theta`

`\lambda = 4.8* sin 42^0`

`\lambda = 3.21 \ cm`

the wavelength of microwaves is equal to
`\lambda = 3.21 \ cm`