Question

A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 900 kg car after the collision if the 600 kg car moves left at .714 m/s?

Answer 1

`\mathrm{v}_(2) \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}`

Step-by-step explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

`m_(1) v_(1)=m_(2) v_(2)`

`\mathrm{m}_(1) \text { and } \mathrm{m}_(2) \text { are masses of the object }`

`\mathrm{v}_(1) \text { velocity before the collision }`

`\mathrm{v}_(2) \text { velocity after the collision }`

`\mathrm{m}_(1)=600 \mathrm{kg}`

`\mathrm{m}_(2)=900 \mathrm{kg}`

`\text { Velocity before the collision } v_(1)=5 \mathrm{m} / \mathrm{s}`

`600 * 5=900 * v_(2)`

`3000=900 * v_(2)`

`\mathrm{v}_(2)=(3000)/(900)`

`\mathrm{v}_(2)=3.3 \mathrm{m} / \mathrm{s}`

`\mathrm{v}_(2) \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}`