Question

An automobile engine provides 527 Joules of work to push the pistons. In this process the internal energy changes by -2886 Joules. Calculate q for the engine. This represents the amount of heat that must be carried away by the cooling system. q = Joules

Answer 1

According to first law of thermodynamics:

= Change in internal energy = -2886 J

q = heat absorbed or released = ?

w = work done or by the system

w = work done by the system= {Work is done by the system as the final volume is greater than initial volume and is negative}

w = -527 J

q = ?

{Heat released by the system is negative}

Thus the amount of heat released by the system and carried away by the cooling system is -2359 JoulesAnswer:

Step-by-step explanation:

Answer 2

Answer: -2359 Joules

Step-by-step explanation:

According to first law of thermodynamics:

`\Delta E=q+w`

`\Delta E`= Change in internal energy = -2886 J

q = heat absorbed or released = ?

w = work done or by the system

w = work done by the system=
`-P\Delta V` {Work is done by the system as the final volume is greater than initial volume and is negative}

w = -527 J

q = ?

`-2886=q+(-527)`

`q=-2359J` {Heat released by the system is negative}

Thus the amount of heat released by the system and carried away by the cooling system is -2359 Joules