What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.) 301.44 ft 2 502.4 ft 2 200.96 ft 2 803.84 ft 2

Question

asked Nov 20, 2020 214k views

2 Answers

Max Noel · Answer 1 · 2020-11-26T19:47:09+0000

Answer:

Surface area of cone is
$502.4\ ft^2$

Explanation:

Given:

radius of a cone (r) = 8 feet

slant height of cone (l) = 12 feet

We need to find the surface area of cone.

Total surface area of cone = Area of circle
Area of curved surface

Now we know that,

Area of circle =
$\pi r^2$

Area of curved surface =
$\pi rl$

Hence Total surface area of cone =
$\pi r^2+\pi rl=\pi r(r+l) = 3.14 * 8 (8+12)=3.14*8*20= 502.4 \ ft^2$

Surface area of cone is
$502.4\ ft^2$ .