Question

a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fraction did the team win ?

Answer 1

The school net ball team drew 2 matches. The team won
`(5)/(8)` of total matches played

Solution:

Given, A school netball team won ten matches, lost four and drew
`(1)/(8)` of the total played

Let the total number of matches played be "n"

Number of matches drawn =
`(1)/(8)` of n

Total matches played = number of won matches + number of lost matches + number of drawn matches

`\begin{array}{l}{n=10+4+(1)/(8) n} \\\\ {n-(1)/(8) n=10+4}\end{array}`

Taking "n" as common from left hand side,

`\begin{array}{l}{\mathrm{n}\left(1-(1)/(8)\right)=14} \\\\ {\mathrm{n} * (8-1)/(8) \quad 14} \\\\ {\mathrm{n} * (7)/(8)=14} \\\\ {\mathrm{n}=16}\end{array}`

So, they played 16 matches in total

Number of matches drawn =
`(1)/(8)` of n =
`(1)/(8) * 16 = 2`
`\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=(10)/(16)=(5)/(8)`

`\text { Hence, the team drew } 2 \text { matches and won } (5)/(8) \text { of total played matches. }`