The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins A) 0.0011 B) 84.9 C) 0.0118 D) 0.000013

Question

asked Dec 2, 2020 149k views

1 Answer

FoxyError · Answer 1 · 2020-12-06T21:48:14+0000

The mean is 0.0118 approximately. So option C is correct

Given that , The probability of winning a certain lottery is
(1)/(77076) for people who play 908 times

We have to find the mean number of wins

$\text { The probability of winning a lottery }=(1)/(77076)$

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

$n=908, \text { probability } \mathrm{p}=(1)/(77076)$

$\text { Then, binomial mean }=n * p$

$\begin{array}{l}{\mu=908 * (1)/(77076)} \\\\ {\mu=(908)/(77076)} \\\\ {\mu=0.01178}\end{array}$

Hence, the mean is 0.0118 approximately. So option C is correct.