Question

3) f(a) = a3+ 3a² + 2a + 8 at a=-3

Answer 1

2

Explanation:

To evaluate f(a) when a = - 3 substitute a = - 3 into f(a)

f(- 3) = (- 3)³ + 3(- 3)² + 2(- 3) + 8 = - 27 + 27 - 6 + 8 = 2