asked 105k views
2 votes
A hunter on a frozen, essentially frictionless pond uses a rifle that shoots 4.20 g bullets at 965 m/s. The mass of the hunter (including his gun) is 72.5 kg, and the hunter holds tight to the gun after firing it. Find the recoil velocity of the hunter if he fires the rifle (a) horizontally and (b) at 56.0∘ above the horizontal.

1 Answer

7 votes

Answer:

a)
V_H=0.056 (-i)m/s

b)
V_H=0.031 (-i)m/s

Step-by-step explanation:

By conservation of the linear momentum:


P_o = P_f


0 = M_H*V_H+m_b*V_b


V_H = m_b/M_H*V_b

When the bullet is shot horizontally
V_b = 965m/s


V_H = -0.056m/s

When the bullet is shot at 56.0° above the horizontal,


V_b = 965*[cos(56),sin(56)]m/s=[539.62;800.02]m/s

Since on the y-axis ground will absorb the shock, we only make the calculations on the x-axis:


V_H = -0.031m/s


V_H = -0.056m/s

answered
User MisterMetaphor
by
7.9k points
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