Question

Calculate the conductance of a conduit whose cross-sectional area is 2.0 cm2 and whose length is 9.0 cm if its conductivity is 0.70 ohm-1cm-l. G = _____ ohm-1 0.32 0.31 0.16 6.4

Answer 1

G = 0.16

Step-by-step explanation:

G=0.7/(9/2)

G=0.16

Answer 2

`0.16 ohm^(-1)`

Step-by-step explanation:

Cell constant, k is given by,
`k={L}{A}` where L is length and A is area. Substituting A for
`2 cm^(2)` and L for 9 cm we obtain

`k=\frac {9}{2}=4.5 cm^(-1)`

Conductance, C is given by dividing conductivity by cell constant hence

`C=\frac {R}{k}`

Substituting 0.7 for R we obtain

`C=\frac {0.7}{4.5}= 0.155555556 ohm^(-1)\approx 0.16 ohm^(-1)`