Question

Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths of the rest in the third. Thus he is left with . . . . .. ths of his money:

(a) 4/15
(b) 4/35
(c) 14/35
(d) 24/35

Answer 1

Khalid is left with b) 4/35 ths of his money.

Step-by-step explanation:

To calculate how much money Khalid is left with after each game, we need to calculate the amount he loses in each game and subtract it from the remaining amount. Let the original money be x , then

Let's start with the first game:

Khalid loses 1/3rd of his money. So, he has 2/3rd of his money remaining.

In the second game, he loses 3.5ths of the remainder.

3/5 of the remainder in the second game implies

3/5 X 2x/3 = 2x/5

The remainder now becomes 2x/3 - 2x/ 5 = 4x/15

4/7 of the rest implies 4/7 X 4x/15 = 16x/105

The rest will therefore be 4x/ 15 - 16x/105

= 4x/35

Answer 2

Answer: 4/35

Step-by-step explanation:

Let the original money be x , then

in the first game Khalid lost 1/3 of x

The remainder will be x - x/3 = 2x/3

3/5 of the remainder in the second game implies

3/5 X 2x/3 = 2x/5

The remainder now becomes 2x/3 - 2x/ 5 = 4x/15

4/7 of the rest implies 4/7 X 4x/15 = 16x/105

The rest will therefore be 4x/ 15 - 16x/105 = 4x/35