Write the standard form of the line that passes through the point (-2,4) and is parallel to x-2y=6

Question

asked Nov 14, 2020 166k views

1 Answer

Carlosm · Answer 1 · 2020-11-18T18:21:59+0000

Answer:

x - 2y + 10 = 0

Explanation:

The equation of parallel line differ only by their constant.

Hence, the equation of the line parallel to
x - 2y - 6 = 0 is nothing but
x - 2y + c = 0 .

When a point passing through this line is given we can substitute the point in this line and get the value for
.

The line passes through
(-2, 4) .

Therefore, we have:
$-2 - 8 + c = 0 \implies c = 10$

Substituting this we get the equation of the parallel line as
x - 2y + 10 = 0 .