Question

Use cramers rule to solve each system of equation:
4x-2y=-6
3x+y=18

Answer 1

The Solution is (3, 9)

Explanation:

Given

`4x-2y=-6`

`3x+y=18`

Now by Using Cramer's Rule

Solving for x:

`x= (Dx)/(D) =\frac{\begin{vmatrix}-6 & -2 &\\18 &1 &\end{vmatrix}}{\begin{vmatrix}4 & -2 &\\3 &1 &\end{vmatrix}} = (-6+36)/(4+6)=(30)/(10)=3`

Solving for y:

`y= (Dx)/(D) =\frac{\begin{vmatrix}4 & -6 &\\3 &18 & \end{vmatrix}}{\begin{vmatrix}4 & -2 &\\3 &1 & \end{vmatrix}} = (72+18)/(4+6)=(90)/(10)=9`

The Solution is (3, 9)