Question

The difference of the product of the polynomials a^2+7a–4 and a–2 and the polynomial a^3+4a^2–29a+11

Answer 1

Explanation:

(a²+7a–4) * (a–2) = (a²+7a–4)* a - (a²+7a–4) *2

= a²*a + 7a*a - 4*a - a²*2 - 7a *2 + 4 *2

= a³ +7a² - 4a - 2a² - 14a +8

= a³ + 5a² - 4a - 14a +8

= a³ + 5a² - 18a +8

a³ + 5a² - 18a +8 - (a³+4a²–29a+11) =a³ + 5a² - 18a +8 -a³- 4a²+29a - 11

= a² + 11a - 3