Question

A line has a slope of -6 and passes through the point (2, 3). What is its equation in

slope-intercept form?

Answer 1

`\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{3})~\hspace{10em} \stackrel{slope}{m}\implies -6 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-6}(x-\stackrel{x_1}{2}) \\\\\\ y-3=-6x+12\implies y=-6x+15`