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Problem 4.079 SI A rigid tank whose volume is 3 m3, initially containing air at 1 bar, 295 K, is connected by a valve to a large vessel holding air at 6 bar, 295 K. The valve is opened only as long as required to fill the tank with air to a pressure of 6 bar and a temperature of 320 K. Assuming the ideal gas model for the air, determine the heat transfer between the tank contents and the surroundings, in kJ.

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User Mhoareau
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1 Answer

4 votes

Answer:


Q_(cv) = -1007.86kJ

Step-by-step explanation:

Our values are,

State 1


V=3m^3\\P_1=1bar\\T_1 = 295K

We know moreover for the tables A-15 that


u_1 = 210.49kJ/kg\\h_i = 295.17kJkg

State 2


P_2 =6bar\\T_2 = 296K\\T_f = 320K

For tables we know at T=320K


u_2 = 228.42kJ/kg

We need to use the ideal gas equation to estimate the mass, so


m_1 = (p_1V)/(RT_1)


m_1 = (1bar*100kPa/1bar(3m^3))/(0.287kJ/kg.K(295k))


m_1 = 3.54kg

Using now for the final mass:


m_2 = (p_2V)/(RT_2)


m_2 = (1bar*100kPa/6bar(3m^3))/(0.287kJ/kg.K(320k))


m_2 = 19.59kg

We only need to apply a energy balance equation:


Q_(cv)+m_ih_i = m_2u_2-m_1u_1


Q_(cv)=m_2u_2-m1_u_1-(m_2-m_1)h_i


Q_(cv) = (19.59)(228.42)-(3.54)(210.49)-(19.59-3.54)(295.17)


Q_(cv) = -1007.86kJ

The negative value indidicates heat ransfer from the system

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User Daniel Kucal
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