Question

In humans, Kinky hair (H++), curly hair (H+), wavy hair H) and straight hair (h) are dominant in that order. Dark hair dominates red hair. A male with wavy red hair, whose mother has straight dark hair, marries a dark haired female with straight hair who has a father with curly red hair. What type of children can they expect to produce, and what is the probability of producing these types of offspring?

Answer 1

The four types of children that they can produce are: wavy dark hair, straight dark hair, wavy red hair and straight red hair. Probability of producing each of these types would be 25%.

Step-by-step explanation:

Answer 2

The four types of children that they can produce are: wavy dark hair, straight dark hair, wavy red hair and straight red hair. Probability of producing each of these types would be 25%.

Step-by-step explanation:

Given,

Dominance: Kinky>curly>wavy>straight

Dark (D) > red(d)

Man has wavy hair so he will have H allele at one locus. His mother has straight hair so he will get one h allele from her. So his genotype is Hh. He has recessive red hair so in colour his genotype is dd. Hence he has a Hhdd genotype.

Woman has straight hair so she will have hh genotype as it is the most recessive trait. Her hair is of dark colour so she will have D dominant allele at one locus. Her father has red hair so she will get one d allele from him. So her genotype for color would be Dd. Hence she has a hhDd genotype

When, Hhdd X hhDd :

Hd hd

hD HdhD hdhD

hd Hdhd hdhd

So the four types of children that they can produce are: wavy dark hair, straight dark hair, wavy red hair and straight red hair. Probability of producing each of these types would be 25%.