A cone shaped funnel can hold 314 cubic inches of water. if the height of the funnel is 12 inches what is the radius of the funnel

Question

asked Mar 22, 2020 124k views

2 Answers

EoLithic · Answer 1 · 2020-03-23T13:41:56+0000

Answer: Radius = 5inches

Explanation:

Volume of a cone = 1/3πr²h

314 = 1/3 X 3.142 X r² X 12

314 = 37.704/3 X r²

314 = 12.568 X r²

r² = 314/ 12.568

r² = 24.9

r = √24.9

r = 4.98 ~ 5 inches

Siggen · Answer 2 · 2020-03-28T10:56:58+0000

The radius of cone shaped funnel is 5 inches

Solution:

To calculate the volume of a cone, we have to multiply the base area, in this case the area of a circle:

$\pi r^2$ by its height and by
(1)/(3)

$\bold{Volume \ of \ a \ cone \ is \ (1)/(3) * \pi* r^2* h}$

Here, volume = 314; h = 12;

we already know
$\bold{\pi=3.14}$

On substituting the vales we get,

314=(1)/(3)* 3.14* r^2* 12

Bringing 3.14 to the L.H.S,

(314)/(3.14)=(1)/(3)* r^2*12

On solving we get,

100=4* r^2

(100)/(4)=r^2

On dividing 100 and 4 we get,

25=r^2

Taking roots on both sides,

$\sqrt25=√(r^2)$

$√(5*5)=\r$

$\therefore r=5$

Hence, radius = 5 inches